3^x-1-3^x=2

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Solution for 3^x-1-3^x=2 equation: 



3^x-1-3^x=2

We move all terms to the left:

3^x-1-3^x-(2)=0

We add all the numbers together, and all the variables

3^x-3^x-3=0

We move all terms containing x to the left, all other terms to the right

3^x-3^x=3

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